6(t-2)^2-5(t-2)+3=0

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Solution for 6(t-2)^2-5(t-2)+3=0 equation: 



6(t-2)^2-5(t-2)+3=0

We multiply parentheses

6(t-2)^2-5t+10+3=0

We add all the numbers together, and all the variables

-5t+6(t-2)^2+13=0

We move all terms containing t to the left, all other terms to the right

-5t+6(t-2)^2=-13

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